SS-V: 3080 Heat Conduction with Temperature-dependent Conductivity

Test No. VT09Calculate the average heat flux through a slab of thickness t (0.25 feet) within the temperature range (100°F and 300°F).

Definition

Figure 1.


The material properties are:

Thermal conductivity of the material varies linearly with respect to temperature (k(T)=C0+C1T)

Where,
  • C0=0.031 BTU/hr-ft-℉
  • C1=0.000031 BTU/hr-ft-℉
Temperature ℉
Thermal Conductivity (BTU/(hr*ft*℉)
100
0.0341
300
0.0403

Results

Calculated the average thermal flux for the slab 1 x 1 x 0.25 feet solid for which the thermal conductivity of an 85% magnesia insulating material is described by the equation k(T)=C0+C1T, valid for temperatures between 100℉ and 300℉.
Table 1. Average thermal flux for the slab
Theory SimSolid % Difference
Thermal flux, [BTU/(hr*ft2) 29.76 30.02 <1

*Reference solution is a 1D model

1 Kreith, F. Principles of Heat Transfer. 2nd ed. P.A.: International Textbook Co., 1959, pg.25